Six point charges are kept at the vertices of a regular hexagon of side $L$ and centre O , as shown in the figure. Given that $\mathrm{K}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}}{\mathrm{L}^2}$, which of the following statement(s) is (are) correct?
Select ALL correct options:
A
the elecric field at O is 6K along OD
B
The potential at O is zero
C
The potential at all points on the line PR is same
D
The potential at all points on the line ST is same.
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
$$
\begin{aligned}
& E_0=6 K(\text { along } O D) \\
& V_0=0
\end{aligned}
$$
Potential on line PR is zero
Ans. (A), (B), (C)
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