Report Issue

JEE Advance2021
Paper-2
Multiple correct answers - Select all that apply
Question
Some standard electrode potentials at 298 K are given below: To a solution containing 0.001 M of $\mathrm{X}^{2+}$ and 0.1 M of $\mathrm{Y}^{2+}$, the metal rods X and Y are inserted (at 298 K ) and connected by a conducting wire. This resulted in dissolution of X . The correct combination(s) of $X$ and $Y$, respectively, is(are) (Given: Gas constant, $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$, Faraday constant, $\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}$ )
Select ALL correct options:
A
Cd and Ni
B
Cd and Fe
C
Ni and Pb
D
Ni and Fe
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
Solution Image
Question Tags
JEE Advance
Chemistry
Easy
Start Preparing for JEE with Competishun