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JEE MAIN 2019
12-04-19_S1
Question
An element has a face-centred cubic (fcc) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is :
Select the correct option:
A
$\frac{3}{2} a$
B
$\frac{a}{2}$
C
a
D
$\sqrt{2} a$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
In FCC, tetrahedral voids are located on the body diagonal at a distance $\frac{\sqrt{3} a}{4}$ of from the corner. Together they form a smaller cube of edge length $\frac{a}{2}$.
Question Tags
JEE Main
Chemistry
Medium
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