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JEE MAIN 2023
13-4-23 S2
Question
The orbital angular momentum of an electron in 3 s orbital is $\frac{x h}{2 \pi}$. The value of $x$ is:
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Solution
Sol. Orbital angular momentum $=\sqrt{1(1+1)} \frac{\mathrm{h}}{2 \pi}$ Value of 1 for $s=0$
Question Tags
JEE Main
Chemistry
Easy
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