The area of the region enclosed between... | Circles

JEE MAIN 2026

23-01-2026 S2

Question

The area of the region enclosed between the circles $x^2+y^2=4$ and $x^2+(y-2)^2=4$ is:

Select the correct option:

$\frac{2}{3}(2 \pi-3 \sqrt{3})$

$\frac{4}{3}(2 \pi-3 \sqrt{3})$

$\frac{4}{3}(2 \pi-\sqrt{3})$

$\frac{2}{3}(4 \pi-3 \sqrt{3})$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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