Area Under Curve | JEE Main 2025 | Circle

JEE MAIN 2025

22-01-2025 SHIFT-1

Question

The area of the region, inside the circle ${(x - 2\sqrt 3 )^2} + {y^2} = 12$ and outside the parabola ${y^2} = 2\sqrt 3 x$ is:

Select the correct option:

$6\pi - 8$

$3\pi - 8$

$6\pi - 16$

$3\pi + 8$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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