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JEE MAIN 2021
22-07-21 S2
Question
The centre of a wheel rolling on a plane surface moves with a speed $v_0$. A particle on the rim of the wheel at the same level as the centre will be moving at a speed $\sqrt{x} v_0$. Then the value of $x$ is $\_\_\_\_$ .
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Question Tags
JEE Main
Physics
Easy
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