The Cut-Off Voltage of..... | JEE Main 2022

JEE MAIN 2022

27-06-2022 S2

Question

The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 $\Omega$ is _______ mA

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Solution

$\begin{aligned} & 1-I(60)-0.6-I(40)=0 \\ & \frac{0.4}{100}=I \\ & I=4 \mathrm{~mA}\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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