The de-Broglie wavelength | MODERN PHYSICS| JEE-MAIN 2021

JEE-MAIN 2021

26-08-2021 S2

Question

The de-Broglie wavelength of a particle having kinetic energy E is $\lambda$. How much extra energy must be given to this particle so that the de-Broglie wavelength reduces to 75% of the initial value ?

Select the correct option:

$\frac{1}{9} \mathrm{E}$

$\frac{7}{9} \mathrm{E}$

$\frac{16}{9} E$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue