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JEE MAIN 2020
05-09-20 S2
Question
The derivative of $\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)$ with respect to $\tan ^{-1}\left(\frac{2 x \sqrt{1-x^2}}{1-2 x^2}\right)$ at $x=\frac{1}{2}$ is :
Select the correct option:
A
$\frac{2 \sqrt{3}}{3}$
B
$\frac{2 \sqrt{3}}{5}$
C
$\frac{\sqrt{3}}{10}$
D
$\frac{\sqrt{3}}{12}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Hard
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