The domain of the function | Function

JEE MAIN 2022

29-06-22 S1

Question

The domain of the function $\cos ^{-1}\left(\frac{2 \sin ^{-1}\left(\frac{1}{4 x^2-1}\right)}{\pi}\right)$ is

Select the correct option:

$R-\left\{-\frac{1}{2}, \frac{1}{2}\right\}$

$(-\infty,-1] \cup[1, \infty) \cup\{0\}$

$\left(-\infty, \frac{-1}{2}\right) \cup\left(\frac{1}{2}, \infty\right) \cup\{0\}$

$\left(-\infty, \frac{-1}{\sqrt{2}}\right] \cup\left[\frac{1}{\sqrt{2}}, \infty\right) \cup\{0\}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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