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JEE-MAIN 2020
03-09-2020 S2
Question
The electric field of a plane electromagnetic wave propagating along the x direction in vacuum is $\vec{E}=E_0 \hat{j} \cos (\omega t-k x)$. The magnetic field $\vec{B}$, at the moment $t=0$ is
Select the correct option:
A
$\overrightarrow{\mathrm{B}}=\mathrm{E}_0 \sqrt{\mu_0 \varepsilon_0} \cos (\mathrm{kx}) \hat{\mathrm{j}} \mid$
B
$\overrightarrow{\mathrm{B}}=\mathrm{E}_0 \sqrt{\mu_0 \varepsilon_0} \cos (\mathrm{kx}) \hat{\mathrm{k}}$
C
$\overrightarrow{\mathrm{B}}=\frac{\mathrm{E}_0}{\sqrt{\mu_0 \varepsilon_0}} \cos (\mathrm{k} x) \hat{\mathrm{k}}$
D
$\vec{B}=\frac{E_0}{\sqrt{\mu_0 \varepsilon_0}} \cos (k x) \hat{j}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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