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JEE MAIN 2019
10-01-2019 S2
Question
The electric field of a plane polarized electromagnetic wave in free space at time t = 0 is given by an expression $\vec{E}(x, y)=10 \hat{j} \cos [(6 x+8 z)]$ The magnetic field $\vec{B}(x, z, t)$ is given by: ( $c$ is the velocity of light)
Select the correct option:
A
$\frac{1}{c}(6 \hat{k}+8 \hat{i}) \cos [(6 x+8 z-10 c t)]$
B
$\frac{1}{c}(6 \hat{k}+8 \hat{i}) \cos [(6 x+8 z+10 c t)]$
C
$\frac{1}{c}(6 \hat{k}+8 \hat{i}) \cos [(6 x-8 z+10 c t)]$
D
$\frac{1}{c}(6 \hat{k}-8 \hat{i}) \cos [(6 x-8 z+10 c t)]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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