The equation of the line.... | Vector & 3D |JEE MAIN 2019

JEE Main 2019

9-01-2019 S1

Question

The equation of the line passing through $(-4,3,1)$, parallel to the plane $x+2 y-z-5=0$ and intersecting the line $\frac{x+1}{-3}=\frac{y-3}{2}=\frac{z-2}{-1}$ is :

Select the correct option:

$\frac{x-4}{2}=\frac{y+3}{2}=\frac{z+1}{4}$

$\frac{x+4}{-1}=\frac{y-3}{1}=\frac{z-1}{1}$

$\frac{x+4}{3}=\frac{y-3}{-1}=\frac{z-1}{1}$

$\frac{x+4}{1}=\frac{y-3}{1}=\frac{z-1}{3}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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