The equilibrium constant |CHEMICAL EQUILIBRIUM|JEE MAIN 2021

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JEE MAIN _2021

_27-07-21

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The equilibrium constant for the reaction $$ \mathrm{A}(\mathrm{~S}) \rightleftharpoons \mathrm{M}(\mathrm{~s})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) $$ is $\mathrm{K}_p=4$. At equilibrium, the partial pressure of $\mathrm{O}_2$ is $\_\_\_\_$ atm. (Round off to the nearest integer)

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