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JEE Advance 2012
paper 2
Question
The general motion of a rigid body can be considered to be a combination of (i) a motioon --- centre of mass about an axis, and (ii) its motion about an instantanneous axis passing through center of mass. These axes need not be stationary. Consider, for example, a thin uniform welded (rigidly fixed) horizontally at its rim to a massless stick, as shown in the figure. Where disc-stick system is rotated about the origin ona horizontal frictionless plane with angular sp-- $\omega$, the motion at any instant can be taken as a combination of (i) a rotation of the centre of mass the disc about the z-axis, and (ii) a rotation of the disc through an instantaneous vertical axis pass through its centre of mass (as is seen from the changed orientation of points P and Q). Both the motions have the same angular speed $\omega$ in the case. Now consider two similar systems as shown in the figure: case (a) the disc with its face ver--- and parallel to x-z plane; Case (b) the disc with its face making an angle of $45^{\circ}$ with $x-y$ plane its horizontal diameter parallel to $x$-axis. In both the cases, the disc is weleded at point $P$, and systems are rotated with constant angular speed $\omega$ about the z-axis.
Which of the following statements about the instantaneous axis (passing through the centre of mass) is correct?
Select the correct option:
A
It is vertical for both the cases (a) and (b).
B
It is verticle for case (a); and is at $45^{\circ}$ to the $x-z$ plane and lies in the plane of the disc for case (b)
C
It is horizontal of case (a); and is at $45^{\circ}$ to the $x-z$ plane and is normal to the plane of the disc for case (b).
D
It is vertical of case (a); and is at $45^{\circ}$ to the $x$ - $z$ plane and is normal to the plane of the disc for case (b).
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Since z- coordinate of any particle is not changing with time so axis must be parellel to z axis
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