$\begin{aligned} & \Delta \mathrm{U}=0 \text { (Cyclic process) } \\ & \Delta \mathrm{Q}=\mathrm{W}=\text { area of } \mathrm{P}-\mathrm{V} \text { curve. } \\ & =\pi \times\left(140 \times 10^3 \mathrm{~Pa}\right) \times\left(140 \times 10^{-6} \mathrm{~m}^3\right) \\ & \Delta \mathrm{Q}=61.6 \mathrm{~J}\end{aligned}$