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JEE MAIN 2025
24-01-2025 SHIFT-2
Question
The hydrocarbon $(\mathrm{X})$ with molar mass $80 \mathrm{~g} \mathrm{~mol}^{-1}$ and $90 \%$ carbon has $\_\_\_\_$ degree of unsaturation.
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Solution
Mass of carbon $=\frac{80 \times 90}{100}=72 \mathrm{gm}$
Number of C-atoms $=\frac{72}{12}=6$
Mass of hydrogen $=\frac{80 \times 10}{800}=8 \mathrm{gm}$
Number of H -atoms $=\frac{8}{1}=8$
So molecular formula $\mathrm{C}_{6} \mathrm{H}_{8}$
D.U. $=6+1-8 / 2=7-4=3$
Question Tags
JEE Main
Chemistry
Easy
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