INDEFINITE INTEGRATION_JEE-Main-2020_040920_S1 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2020

04-09-2020 S1

Question

The integral $\int\left(\frac{x}{x \sin x+\cos x}\right)^2 d x$ is equal to (where C is a constant of integration):

Select the correct option:

$\tan x-\frac{x \sec x}{x \sin x+\cos x}+C$

$\sec x-\frac{x \tan x}{x \sin x+\cos x}+C$

$\tan x+\frac{x \sec x}{x \sin x+\cos x}+C$

$\sec x+\frac{x \tan x}{x \sin x+\cos x}+C$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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