The internal energy of air in $4 m \times 4 m \times 3 m$ sized room at 1 atmospheric pressure will be $\_\_\_\_$ $\times 10^{6} J$.
(Consider air as diatomic molecule)
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Solution
To find the internal energy of gas in the room.
$U=n C_{v} T=n \frac{5 R T}{2}$
$=\frac{5}{2} P V=\frac{5}{2} \times 10^{5} \times 48=12 \times 10^{6} J$
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