The inverse function of... | Function

JEE MAIN 2020

08-01-20 S1

Question

The inverse function of $f(x)=\frac{8^{2 x}-8^{-2 x}}{8^{2 x}+8^{-2 x}}, x \in(-1,1)$, is $\_\_\_\_$ .

Select the correct option:

$\frac{1}{4} \log _e\left(\frac{1-x}{1+x}\right)$

$\frac{1}{4}\left(\log _8 e\right) \log _e\left(\frac{1+x}{1-x}\right)$

$\frac{1}{4} \log _e\left(\frac{1+x}{1-x}\right)$

$\frac{1}{4} \log _8(e) \log _e\left(\frac{1-x}{1+x}\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

Start Preparing for JEE with Competishun