The local maximum value of the function... | Maxima & Minima

JEE MAIN 2021

26-08-2021 S2

Question

The local maximum value of the function $f(x)=\left(\frac{2}{x}\right)^{x^2}, x>0$, is

Select the correct option:

$(2 \sqrt{e})^{\frac{1}{e}}$

$\left(\frac{4}{\sqrt{\mathrm{e}}}\right)^{\frac{\mathrm{e}}{4}}$

$(e)^{\frac{2}{e}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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