The logarithm of equilibrium constant for the reaction $\mathrm{Pd}^{2+}+4 \mathrm{Cl} \rightleftharpoons \mathrm{PdCl}_4^{2-}$ is $\_\_\_\_$ (Nearest integer) Given: $\frac{2.303 R T}{F}=0.06 \mathrm{~V}$ $$ \begin{array}{ll} \mathrm{Pd}_{(\mathrm{aq})}^{2+}+2 \mathrm{e}^{-} \rightleftharpoons \mathrm{Pd}(\mathrm{~s}) & \mathrm{E}^{\circ}=0.83 \mathrm{~V} \\ \mathrm{PdCl}_4^{2-}(\mathrm{aq})+2 \mathrm{e}^{-} \rightleftharpoons \mathrm{Pd}(\mathrm{~s})+4 \mathrm{Cl}^{-}(\mathrm{aq}) & \mathrm{E}^{\circ}=0.65 \mathrm{~V} \end{array} $$