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JEE MAIN 2023
31.01.24 S2
Question
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192
Select the correct option:
A
24
B
32
C
40
D
20
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & R_1=\frac{R_2}{2} \\ & \mathrm{R}_0\left(\mathrm{~A}_1\right)^{1 / 3}=\frac{\mathrm{R}_0}{2}\left(\mathrm{~A}_2\right)^{1 / 3} \\ & \mathrm{~A}_1=\frac{1}{8} \mathrm{~A}_2 \\ & A_1=\frac{192}{8}=24\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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