The $\mathrm{K}_\alpha$ X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atoms with a K electron knocked out is 27.5 KeV, the energy of this atoms when an L electron is knocked out will be _____keV. (Round off to the nearest integer) [h = 4.14 × 10–15 eVs, c = 3 × 108 ms–1]