Ksp for Bismuth Sulphide Bi₂S₃..... | JEE Main 2022

JEE MAIN 2022

25-06-2022 S2

Question

The $\mathrm{K}_{\mathrm{sp}}$ for bismuth sulphide $\left(\mathrm{Bi}_2 \mathrm{~S}_3\right)$ is $1.08 \times 10^{-73}$. The solubility of $\mathrm{Bi}_2 \mathrm{~S}_3$ in $\mathrm{mol} \mathrm{L}^{-1}$ at 298 K is

Select the correct option:

$1.0 \times 10^{-15}$

$2.7 \times 10^{-12}$

$3.2 \times 10^{-10}$

$4.2 \times 10^{-8}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Easy

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