Maximum value of function | MAXIMA AND MINIMA |JEE MAIN 2019

JEE MAIN 2019

11-01-2019 S1

Question

The maximum value of the function $f(x)=3 x^3-18 x^2+27 x-40$ on the set $S=\left\{x \in R: x^2+30 \leq 11 x\right\}$ is

Select the correct option:

A

122

B

-122

C

222

D

-222

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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