The minimum energy that | Atomic Structure

JEE MAIN 2022

25-06-2022 S2

Question

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is $1.3 \times 10^{15} \mathrm{~s}^{-1}$ and $\mathrm{h}=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s}$.]

Select the correct option:

$3.21 \times 10^{-14} \mathrm{~J}$

$6.24 \times 10^{-16} \mathrm{~J}$

$8.58 \times 10^{-19} \mathrm{~J}$

$9.76 \times 10^{-20} \mathrm{~J}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & W=h v \\ & =6.6 \times 10^{-34} \times 1.3 \times 10^{15} \\ & =8.58 \times 10^{-19} \mathrm{~J}\end{aligned}$

Question Tags

JEE Main

Chemistry