IE_JEE-Main 12-4-19_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2019

12-04-2019 S2

Question

The molar solubility of $\mathrm{Cd}(\mathrm{OH})_2$ is $1.84 \times 10^{-5} \mathrm{M}$ in water. The expected solubility of $\mathrm{Cd}(\mathrm{OH})_2$ in a buffer solution of $\mathrm{pH}=12$ is:

Select the correct option:

$1.84 \times 10^{-9} \mathrm{M}$

$6.23 \times 10^{-11} \mathrm{M}$

$\frac{2.49}{1.84} \times 10^{-9} \mathrm{M}$

$2.49 \times 10^{-10} \mathrm{M}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Medium

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