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JEE MAIN 2021
26-08-21 S1
Question
The number of 4f electrons in the ground state electronic configuration of Gd2+ is ________.
[Atomic number of Gd = 64]
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Solution
The electronic configuration of 64 Gd : [Xe] 4f⁷ 5d¹ 6s² So the electronic configuration of 64 Gd²⁺ : [Xe] 4f⁷ 5d⁰ 6s⁰ i.e. the number of f electrons in the ground state electronic configuration of Gd²⁺ is 7.
Question Tags
JEE Main
Chemistry
Easy
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