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JEE MAIN 2021
27-08-21 S1
Question
The number of f electrons in the ground state electronic configuration of Np (Z = 93) is ________. (Nearest integer)
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Solution
$\begin{aligned} & N p=1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 4 s^2 3 d^{10} 4 p^6 5 s^2 4 d^{10} 5 p^6 6 s^2 4^{14 f} 5 d^{10} 6 p^6 7 s^2 5 f^4 6 d^1 \\ & \text { Total no. of 'f' electron }=14 e^{-}+4 e^{-}=18\end{aligned}$
Question Tags
JEE Main
Chemistry
Easy
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