Units & Measurements | JEE Main 2025 Solution

JEE MAIN 2025

23-01-2025 SHIFT-1

Question

The position of a particle moving on x -axis is given by $\text{x}(\text{t})=\text{A}\sin \text{t}+\text{B}{{\cos }^{2}}\text{t}+\text{C}{{\text{t}}^{2}}+\text{D}$ , where t is time. The dimension of $\frac{{ABC}}{D}$ is

Select the correct option:

${{\text{L}}^{2}}$

${{\text{L}}^{2}}~{{\text{T}}^{{-2}}}$

${{\text{L}}^{3}}~{{\text{T}}^{{-2}}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Video Solution

BY competishun

Watch Solution

YouTube

Report Issue