The position of a..... | JEE Main 2023

JEE MAIN 2023

15-04-2023 S1

Question

The position of a particle related to time is given by $x=\left(5 t^2-4 t+5\right) m$. The magnitude of velocity of the particle at $\mathrm{t}=2 \mathrm{~s}$ will be.

Select the correct option:

$10 \mathrm{~ms}^{-1}$

$14 \mathrm{~ms}^{-1}$

$16 \mathrm{~ms}^{-1}$

$06 \mathrm{~ms}^{-1}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue