Parabola | JEE Main 2025 | Smallest Touching Circle Radius

JEE MAIN 2025

03-04-2025 SHIFT-1

Question

The radius of the smallest circle which touches the parabolas $y = {x^2} + 2{\rm{ and }}x = {y^2} + 2{\rm{ is }}$

Select the correct option:

$\frac{{7\sqrt 2 }}{2}$

$\frac{{7\sqrt 2 }}{8}$

$\frac{{7\sqrt 2 }}{{16}}$

$\frac{{7\sqrt 2 }}{4}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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