MP_01-09-21_JEE (MAIN)-2021_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2021

01-09-21 S2

Question

The ranges and heights for two projectiles projected with the same initial velocity at angles $42^{\circ}$ and $48^{\circ}$ with the horizontal are $\mathrm{R}_1, \mathrm{R}_2$ and $\mathrm{H}_1, \mathrm{H}_2$ respectively. Choose the correct option :

Select the correct option:

$\mathrm{R}_1>\mathrm{R}_2$ and $\mathrm{H}_1=\mathrm{H}_2$

$\mathrm{R}_1=\mathrm{R}_2$ and $\mathrm{H}_1<\mathrm{H}_2$

$\mathrm{R}_1<\mathrm{R}_2$ and $\mathrm{H}_1<\mathrm{H}_2$

$\mathrm{R}_1=\mathrm{R}_2$ and $\mathrm{H}_1=\mathrm{H}_2$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Range $\mathrm{R}=\frac{\mathrm{u}^2 \sin 2 \theta}{\mathrm{~g}}$ and same for $\theta$ and $90-\theta$ So same for $42^{\circ}$ and $48^{\circ}$ Maximum height $\mathrm{H}=\frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{~g}}$ H is high for higher $\theta$ So H for $48^{\circ}$ is higher than H for $42^{\circ}$ Option (2)

Question Tags

JEE Main

Physics

Easy

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