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JEE MAIN 2019
12-04-2019 S2
Question
The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are, respectively
Select the correct option:
A
4 : 2 : 3
B
4 : 2 : 1
C
8 : 1 : 6
D
1 : 2 : 4
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
No. of atoms in
Simple cubic unit cell $=\frac{1}{8} \times 8=1$
B.C.C. unit cell $=\frac{1}{8} \times 8+1 \times 1=2$
FCC unit cell $=\frac{1}{8} \times 8+\frac{1}{2} \times 6=4$
Question Tags
JEE Main
Chemistry
Easy
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