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JEE Advance2021
Paper-2
Question
The reaction of $\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_8\right]$ with freshly prepared $\mathrm{FeSO}_4$ solution produces a dark blue precipitate called Turnbull's blue. Reaction of $\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$ with the $\mathrm{FeSO}_4$ solution in complete absence of air produces a white precipitate X , which turns blue in air. Mixing the $\mathrm{FeSO}_4$ solution with $\mathrm{NaNO}_3$, followed by a slow addition of concentrated $\mathrm{H}_2 \mathrm{SO}_4$ through the side of the test tube produces a brown ring.Among the following, the brown ring is due to the formation of
Select the correct option:
A
$\left[\mathrm{Fe}(\mathrm{NO})_2\left(\mathrm{SO}_4\right)_2\right]^{2-}$
B
$\left[\mathrm{Fe}(\mathrm{NO})_2\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{3+}$
C
$\left[\mathrm{Fe}(\mathrm{NO})_4\left(\mathrm{SO}_4\right)_2\right]$
D
$\left[\mathrm{Fe}(\mathrm{NO})\left(\mathrm{H}_2 \mathrm{O}\right)_5\right]^{2+}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Advance
Chemistry
Easy
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