The shortest distance between | Vector & 3D | JEE MAIN 2020

JEE MAIN 2020

08-01-20 S1

Question

The shortest distance between the lines
$\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}$ and $\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{2}$ is

Select the correct option:

A

$2 \sqrt{30}$

B

$\frac{7}{2} \sqrt{30}$

C

$3 \sqrt{30}$

D

3

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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