Shortest distance between| Vector & 3D | JEE - MAIN - 2020

JEE MAIN 2020

06-09-2020_S1

Question

The shortest distance between the lines $\frac{x-1}{0}=\frac{y+1}{-1}=\frac{z}{1}$ and $x+y+z+1=0,2 x-y+z+3=0$ is :

Select the correct option:

A

$\frac{1}{\sqrt{2}}$

B

1

C

$\frac{1}{\sqrt{3}}$

D

$\frac{1}{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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