The solubility product of Cr(OH)₃ at 298 K... | Ionic Equilibrium | JEE Main

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JEE MAIN 2020

09-01-2020 S2

Question

The solubility product of $\mathrm{Cr}(\mathrm{OH})_3$ at 298 K is $6.0 \times 10^{-31}$. The concentration of hydroxide ions in a saturated solution of $\mathrm{Cr}(\mathrm{OH})_3$ will be

Select the correct option:

A

$\left(2.22 \times 10^{-31}\right)^{1 / 4}$

B

$\left(18 \times 10^{-31}\right)^{1 / 2}$

C

$\left(18 \times 10^{-31}\right)^{1 / 4}$

D

$\left(4.86 \times 10^{-29}\right)^{1 / 4}$

✓ Correct! Well done.

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