Differential Equations | JEE Main Solution

JEE MAIN 2025

07-04-2025 SHIFT-1

Question

Let $y = y(x)$ be the solution curve of the differential equation $x\left( {{x^2} + {e^x}} \right)dy + \left( {{{\rm{e}}^x}(x - 2)y - {x^3}} \right){\rm{d}}x = 0,x > 0$ , passing through the point (1,0). Then y(2) is equal to

Select the correct option:

$\frac{4}{{4 + {e^2}}}$

$\frac{2}{{2 + {e^2}}}$

$\frac{2}{{2 - {e^2}}}$

$\frac{4}{{4 - {e^2}}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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