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_ JEE MAIN_2019_
10-04-2019-S-1
Question
The sum $$ \frac{3 \times 1}{1^2}+\frac{5 \times\left(1^3+2^3\right)}{1^2+2^2}+\frac{7 \times\left(1^3+2^3+3^3\right)}{1^2+2^2+3^2}+\ldots $$ upto $10^{\text {th }}$ term, is.
Select the correct option:
A
620
B
600
C
680
D
660
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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