The sum of oxidation state of the metals in $\mathrm{Fe}(\mathrm{CO})_5, \mathrm{VO}^{2+}$ and $\mathrm{WO}_3$ is ______
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Solution
$\stackrel{(0)}{\mathrm{Fe}}(\mathrm{CO})_5 \stackrel{(+4)}{\mathrm{V}} \mathrm{O}^{2+} \stackrel{(+6)}{\mathrm{W}} \mathrm{O}_3$
So, Sum of oxidation state = 0 + 4 + 6 = 10
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