The two thin coaxial rings, each | Electrostatics|JEE-MAIN

JEE-MAIN 2021

26-08-2021 S2

Question

The two thin coaxial rings, each of radius 'a' and having charges +Q and –Q respectively are separated by a distance of 's'. The potential difference between the centres of the two rings is :

Select the correct option:

$\frac{Q}{2 \pi \varepsilon_0}\left[\frac{1}{a}+\frac{1}{\sqrt{s^2+a^2}}\right]$

`$\frac{\mathrm{Q}}{4 \pi \varepsilon_0}\left[\frac{1}{\mathrm{a}}+\frac{1}{\sqrt{\mathrm{~s}^2+\mathrm{a}^2}}\right]$

$\frac{Q}{4 \pi \varepsilon_0}\left[\frac{1}{a}-\frac{1}{\sqrt{s^2+a^2}}\right]$

$\frac{Q}{2 \pi \varepsilon_0}\left[\frac{1}{a}-\frac{1}{\sqrt{s^2+a^2}}\right]$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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