The value of cot(π/24) is... | Trigonometry | JEE Main

JEE MAIN 2021

25-07-2021 S2

Question

The value of $\cot \frac{\pi}{24}$ is :

Select the correct option:

A

$\sqrt{2}+\sqrt{3}+2-\sqrt{6}$

B

$\sqrt{2}+\sqrt{3}+2+\sqrt{6}$

C

$\sqrt{2}-\sqrt{3}-2+\sqrt{6}$

D

$3 \sqrt{2}-\sqrt{3}-\sqrt{6}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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