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JEE MAIN 2022
27-6-2022 S2
Question
The value of $\cot \left(\sum_{n=1}^{50} \tan ^{-1}\left(\frac{1}{1+n+n^2}\right)\right)$ is :
Select the correct option:
A
26/25
B
25/26
C
50/51
D
52/51
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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