The value of lim h→0 of given trigonometric expression... | Limits

JEE MAIN 2021

26-02-2021 S1

Question

The value of $\lim _{h \rightarrow 0} 2\left\{\frac{\sqrt{3} \sin \left(\frac{\pi}{6}+h\right)+\cos \left(\frac{\pi}{6}+h\right)}{\sqrt{3} h(\sqrt{3} \cos h-\sin h)}\right\}$ is

Select the correct option:

$\frac{4}{3}$

$\frac{2}{\sqrt{3}}$

$\frac{3}{4}$

$\frac{2}{3}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

Start Preparing for JEE with Competishun

Report Issue