Sequences and Series JEE Main Solution

JEE MAIN 2025

29-01-2025 SHIFT-1

Question

The value of $\mathop {\lim }\limits_{n \to \infty } \left( {\sum\limits_{k = 1}^n {\frac{{{k^3} + 6{k^2} + 11k + 5}}{{(k + 3)!}}}} \right)$ is:

Select the correct option:

4/3

7/3

5/3

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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