The values of... | CHEMICAL EQUILIBRIUM

JEE Main 2019

10-01-2019 S1

Question

The values of $\frac{K_p}{K_c}$ for the following reactions at 300 K are, respectively (At $300 \mathrm{~K}, \mathrm{RT}=24.62 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1}$ ) $$ \begin{aligned} & \mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{~g}) \\ & \mathrm{N}_2 \mathrm{O}_4(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_2(\mathrm{~g}) \\ & \mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g}) \end{aligned} $$

Select the correct option:

$24.62 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1}, 606.0 \mathrm{dm}^6 \mathrm{~atm}^2 \mathrm{~mol}^{-2}, 1.65 \times 10^{-3} \mathrm{dm}^{-6} \mathrm{~atm}^{-2} \mathrm{~mol}^2$

$124.62 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1}, 1.65 \times 10^{-3} \mathrm{dm}^{-6} \mathrm{~atm}^{-2} \mathrm{~mol}^2$

$124.62 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1}, 606.0 \mathrm{dm}^6 \mathrm{~atm}^2 \mathrm{~mol}^{-2}$

$14.1 \times 10^{-2} \mathrm{dm}^{-3} \mathrm{~atm}^{-1} \mathrm{~mol}, 606 \mathrm{dm}^6 \mathrm{~atm}^2 \mathrm{~mol}^{-2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Medium

Start Preparing for JEE with Competishun

Report Issue