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JEE MAIN 2021
25-02-2021 S2
Question
The wavelength of an X-ray beam is $10 \A$. The mass of a fictitious particle having the same energy as that of the X -ray photons is $\frac{\mathrm{x}}{3}^{\mathrm{h} \mathrm{kg}}$. The value of $x$ is $\_\_\_\_$ . (h = Planck's constant)
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Solution
$\begin{aligned} & \frac{\mathrm{hc}}{\lambda}=\mathrm{mc}^2 \\ & \mathrm{~m}=\frac{\mathrm{h}}{\mathrm{c} \lambda}\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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